From 096e1683a3a04b9936467a889b1e46fdef8ecb89 Mon Sep 17 00:00:00 2001 From: jerryzeng Date: Sun, 16 Aug 2026 14:42:35 +0800 Subject: [PATCH] =?UTF-8?q?hybridPosePositioning=20version=201.3.6=20:=20?= =?UTF-8?q?=E5=9C=A81.3.5=E7=89=88=E6=9C=AC=E7=9A=84=E5=9F=BA=E7=A1=80?= =?UTF-8?q?=E4=B8=8A=E6=A0=B9=E6=8D=AE=E7=8E=B0=E5=9C=BA=E6=95=B0=E6=8D=AE?= =?UTF-8?q?=E4=BF=AE=E6=AD=A3=E4=BA=86=E8=BD=AC=E5=AD=90=E9=92=A2=E8=8A=AF?= =?UTF-8?q?=E5=AE=9A=E4=BD=8D=E7=AE=97=E6=B3=95=E4=B8=AD=E7=9A=84bug?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- sourceCode/hybridPosePositioning.cpp | 9 +++++---- 1 file changed, 5 insertions(+), 4 deletions(-) diff --git a/sourceCode/hybridPosePositioning.cpp b/sourceCode/hybridPosePositioning.cpp index 50288f4..007c448 100644 --- a/sourceCode/hybridPosePositioning.cpp +++ b/sourceCode/hybridPosePositioning.cpp @@ -16,7 +16,8 @@ //version 1.3.3 : 改进了海瑞马锥形工件定位算法,优化的ROI重叠时的处理逻辑 //version 1.3.4 : 修正了转子钢芯定位算法中的bug //version 1.3.5 : 根据现场数据修正了转子钢芯定位算法中的bug -std::string m_strVersion = "HybridPositioning 1.3.5"; +//version 1.3.6 : 在1.3.5版本的基础上根据现场数据修正了转子钢芯定位算法中的bug +std::string m_strVersion = "HybridPositioning 1.3.6"; const char* wd_hybridPositioningVersion(void) { return m_strVersion.c_str(); @@ -370,7 +371,7 @@ WD_workpieceInfo _computeWorkpiecePose( SSG_lineSegParam filterSegPara; filterSegPara.distScale = 0; - filterSegPara.segGapTh_y = topSeg_maxWidth; + filterSegPara.segGapTh_y = 5.0; //超过5.0mm间隔视为新分段 filterSegPara.segGapTh_z = workpieceParam.height / 2; //垂直 @@ -596,7 +597,7 @@ WD_workpieceInfo _computeWorkpiecePose( //垂直扫描处理 for (int line = 0; line < lineNum; line++) { - if (line == 83) + if (line == 47) int kkk = 1; int mostLeftSegId = -1; //对于垂直扫描,实际上是最上面 int mostRightSegId = -1;//对于垂直扫描,实际上是最下面 @@ -1146,7 +1147,7 @@ void wd_HRM_RotorCorePositioning( std::vector allWorkpiece; for (int idx = 0; idx < objNum; idx++) { - if (idx == 47) + if (idx == 44) int kkk = 1; WD_objArea2D& obj_roi = objROIs[idx]; double cx = (obj_roi.roi.left + obj_roi.roi.right) / 2;